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blsea [12.9K]
3 years ago
12

Using the elimination method to solve the following system of equation.

Mathematics
2 answers:
wolverine [178]3 years ago
8 0
First step, multiply the bottom one by 8
 it should look like
8x -16y =0
8x + 16y = 24

Then jsut work the problem
the 16's cancel out, and the 8's add to 16, and the 24 add's to 0 making it 24 still.
So it should look like 
16x = 24.
making your answer 1.5<span />
Ipatiy [6.2K]3 years ago
7 0
Can someone please hop on over to my question?
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It is a straight line of positive gradient that passes through the origin
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3 years ago
The length of time that it takes for a ferry to reach a summer resort from the mainland is approximately normally distributed wi
kaheart [24]

Answer:

A) 0.10565

B) 0.33846

C)

Step-by-step explanation:

The length of time that it takes for a ferry to reach a summer resort from the mainland is approximately normally distributed with a mean of 2 hours and a standard deviation of 12 minutes.

Note that, all units must be in minutes

We solve this question using z score formula

= z = (x-μ)/σ

where

x is the raw score

μ is the population mean = 2 hours

Converting to minutes

1 hour = 60 minutes

2 hour = x

Cross Multiply

x = 2 × 60 minutes

x = 120 minutes

Mean = 120 minutes

σ is the population standard deviation = 12 minutes

Over many past trips, what proportion (area) of times has the ferry reaches the island in

A) less than 1 hour, 45 minutes?

Converting 1 hour 45 minutes to minutes

60 minutes = 1 hour

Hence:

60 + 45 minutes = 105 minutes

For x < 105 minutes

= 105 - 120/12

= -1.25

Probability value from Z-Table:

P(x<105) = 0.10565

B) more than 2 hours, 5 minutes?

Converting 2 hours 5 minutes to minutes

Hence:

1 hour = 60 minutes

2 hour = x

Cross Multiply

x = 2 × 60 minutes

x = 120 minutes

Hence:

120 + 5 minutes = 125 minutes

For x < 125 minutes

z = 125 - 120/12

z = 0.41667

Probability value from Z-Table:

P(x<125) = 0.66154

P(x>125) = 1 - P(x<125) = 0.33846

C) between 1 hour, 50 minutes and 2 hours, 20 minutes?

Converting 1 hour, 50 minutes to minutes

= 60 minutes = 1 hour

Hence:

60 + 50 minutes = 110 minutes

For x = 110 minutes

= 110 - 120/12

= -0.83333

Probability value from Z-Table:

P(x = 110) = 0.20233

Converting 2 hours, 20 minutes to minutes

= 1 hour = 60 minutes

2 hour = x

Cross Multiply

x = 2 × 60 minutes

x = 120 minutes

Hence:

120 + 20 minutes = 140 minutes

For x = 140minutes

z = 140 - 120/12

= 1.66667

Probability value from Z-Table:

P(x = 140) = 0.95221

4 0
3 years ago
1. f(x)=0.5x-1.5x +1I 4x&lt;-1-1sx53 x&gt;3<br>​
disa [49]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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There are 64 pretzels in a 16-ounce bag of chocolate-covered pretzels.
Shkiper50 [21]

Answer:

64 pretzels in a 16 oz bag

1 oz will contain 64/16 pretzels = 4

5 oz will therefore contain 4 x 5 = 20 pretzels

Step-by-step explanation:

See here for a deeper explanation! ^^

Hopefully it helps :)

brainly.com/question/200543

8 0
3 years ago
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The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T
Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. In this problem, \sigma = 0.25

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

M = z*\frac{\sigma}{\sqrt{n}}

0.1 = 1.96*\frac{0.25}{\sqrt{n}}

0.1\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.1}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}

n = 24.01

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

M = z*\frac{\sigma}{\sqrt{n}}

0.06 = 1.96*\frac{0.25}{\sqrt{n}}

0.06\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.06}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}

n = 66.7

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

M = z*\frac{\sigma}{\sqrt{n}}

0.05 = 1.96*\frac{0.25}{\sqrt{n}}

0.05\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.05}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}

n = 96.04

Rounding up, 97

8 0
3 years ago
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