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Sergeeva-Olga [200]
3 years ago
9

20≥−3.2(c−4.3) what is solution.

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0
20 ≥ -3.2(c - 4.3)
20 ≥ -3.2c + 13.76
6.24 ≥ -3.2c
-1.95 ≤ c
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Can someone help me figure this out plz? Thank you!!!
Lina20 [59]
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Answer b.
5 0
3 years ago
How do I get this answer (4x2-6y2-7)(6x2+7)
babymother [125]
<span>Simplifying 4x2y + 12xy2 + 9y3 Reorder the terms: 12xy2 + 4x2y + 9y3 Factor out the Greatest Common Factor (GCF), 'y'. y(12xy + 4x2 + 9y2) Factor a trinomial. y((2x + 3y)(2x + 3y))

Final result:
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5 0
3 years ago
How to do this question
Bas_tet [7]

Answer:

x

Step-by-step explanation:

factor out both equations and then cancel any of the common factors. You should be left with 4x/4, which simplified is x

7 0
2 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Please help me i'll give 20 points to whoever helps me answer all 4 of them and brainly
Brilliant_brown [7]

Answer:

G - number of arrangements

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7 0
2 years ago
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