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AleksandrR [38]
3 years ago
15

Can someone help me with 4 and 5 please

Mathematics
1 answer:
alexandr1967 [171]3 years ago
5 0
I'm honestly in a crunch my answer is useless


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Can someone please solve this by graphing​
balu736 [363]

XY - X + 2Y -2 =X(Y-1) + 2(Y-1) = 2X(Y-1)

4 0
2 years ago
The ratio is 5:3 there is 20 girls and 16 boys if three girls are absent what would the ratio be​
Leokris [45]

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7 0
3 years ago
Read 2 more answers
To find the quotient 5/7 divided by 1/3 multiply..
cestrela7 [59]

Answer:

Multiply 5/7 by 3

Step-by-step explanation:

To find the quotient (division) multiply by the reciprocal. The reciprocal of 1/3 is 3.

8 0
3 years ago
Find the sum of the first 8 terms of the following sequence. Round to the nearest hundredth if necessary
AlexFokin [52]

The sum of the first 8 terms is 2.51 to the nearest hundredth

Step-by-step explanation:

In the geometric sequence there is a constant ratio between each two consecutive terms

The formula of the sum of n terms of a geometric sequence is:

S_{n}=\frac{a(1-r^{n})}{1-r} , where

  • a is the first term
  • r is the constant ratio between the consecutive terms

∵ The sequence is 6 , -5 , 25/6 , .............

∵ -5 ÷ 6 = \frac{-5}{6}

∵ \frac{25}{6} ÷ -5 = \frac{-5}{6}

- There is a constant ratio between the consecutive terms

∴ The sequence is a geometric sequence

∵ The first term is 6

∴ a = 6

∵ The constant ratio is \frac{-5}{6}

∴ r =  \frac{-5}{6}

∵ We need to find the sum of 8 terms

∴ n = 8

- Substitute the values of a, r and n in the rule above

∴ S_{8}=\frac{6[1-(\frac{-5}{6})^{8}]}{1-(\frac{-5}{6})}

∴ S_{8}=2.511595508

- Round it to the nearest hundredth

∴ S_{8}=2.51

The sum of the first 8 terms is 2.51 to the nearest hundredth

Learn more:

You can learn more about the sequences in brainly.com/question/7221312

#LearnwithBrainly

3 0
3 years ago
ABCD is a parallelogram.
kow [346]

Opposite sides of a parallelogram are equal lengths, so ...

... AB = CD

... 6x +30 = 2y -10

and

... BC = AD

... 2x -5 = y -35

_____

The equations can be put in standard form to get

... 3x -y = -20

... 2x -y = -30

Subtracting the second from the first, we get

... x = 10

Solving for y, we have

... y = 2x+30 = 2·10 +30 = 50

The values of x and y are x=10, y=50.

_____

AB = 6x+30 = 90

BC = 2x-5 = 15

3 0
3 years ago
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