You have to know that the graph of the arctangent function is a flat S-shaped curve that goes through (0, 0) and has asymptotes at ±π/2. The factor of 2 that multiplies it here expands it vertically so the asymptotes are at ±π. The +3 added to the x causes it to be shifted to the left by 3 units.
(Pls give brainliest! :D)
Answer:
<em>B</em>
Step-by-step explanation:
<em>You know that the graph intercepts at the point of (4,-2)</em>
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<em>Where x = 4 and y = -2.</em>
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<em>This means that whenever you plug a value of x in the equation it should give the value of y.</em>
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<em>For example when you plug x= 4 into the equation (B), it should look like this.</em>
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<em>4- y = 6, solving for y gives us the value negative 2.</em>
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<em>This means that it does give us this point, however, as the graph shows us, both lines meet at the point which means that both equation should give us this point.</em>
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<em>If we substitute x = 4 in the second equation of b, we should be able to get 3(4) + 4y = 4. Solving for y gives us -2.</em>
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Hope this helps!
-<em>Yumi</em>
Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :
where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have
Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are
and
Thus, the required solution is
Answer:
14 = x
Step-by-step explanation:
-2 on both sides you get 7 = x/2, multiply both sides by 2 and you get 14 = x
For the first one...
1,15
2,30
3,20
and for the second one is the same as the first one.
EXTRA CREDIT:
Week one increases by 15, week two increases by 15 but week three decreases by 15. The total miles ran would be 15 miles
15+15=30 30-15=15 miles
