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2 years ago

15

A bus travels with a constant speed of 48 miles per hour. How long will it take to travel 60 miles? Write your answer as a decim

al number.

2 answers:

mrs_skeptik [129]2 years ago

4 0

1 hour and 15 minutes

IrinaK [193]2 years ago

4 0

It will take an hour and 25 min.

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Answer dis please- Thanks

hodyreva [135]

Answer:

Since we know that ABCD ~ EFGH, we have the ratios:

EF/AB = GH/CD

=> 0.4/1.2 = x/1.8

=> x = (1.8 . 0.4)/1.2 = 0.6

So x = 0.6

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2 years ago

It takes teccance 5 minutes to read 1 pages. Of terrance read for about an hour estimate how many pages he should read

Semenov [28]

Answer:

12

Step-by-step explanation:

That’s what I got

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2 years ago

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Y: 2x+3+9x+2<br> Simplify this

BARSIC [14]

Answer:

y=16x ??

Step-by-step explanation:

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2 years ago

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Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

Can I get help with this please

drek231 [11]

Answer:

3) 1 5/6 mi

4) a. 4 cm, 6 ft

b. 6.4 cm, 9.6 ft

c. same as part a

Step-by-step explanation:

3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...

4×1/3 + 4×1/8 = 4/3 + 4/8

= 1 1/3 + 1/2 = 1 2/6 + 3/6

= 1 5/6 . . . . . miles

___

4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.

a. 8 cm = 4 cm + x

8 cm - 4 cm = x = 4 cm

The distance in the room is ...

(4 cm)×(1.5 ft/cm) = 6 ft

b. 10.3 cm = 3.9 cm + y

10.3 cm - 3.9 cm = y = 6.4 cm

The distance in the room is ...

(6.4 cm)×(1.5 ft/cm) = 9.6 ft

c. The answer to part b was obtained in the same way as the answer to part a. The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.

3 0

3 years ago