What is the solution to |x + 2| < 1?

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

8 0

Answer:

-3 <x <-1

Step-by-step explanation:

|x + 2| < 1

There are two solutions, one positive and one negative ( remember to flip the inequality for the negative)

x+2 <1 and x+2 > -1

Subtract 2 from each side

x+2-2 < 1-2 and x+2-2 > -1-2

x < -1 and x >-3

-3 <x <-1

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