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3 years ago

Two less than five times a number is 28. what is the number

2 answers:

7 0

The number is 6 because five times 6 is 30, and 30 minus 2 is 28. You could also solve this backwards in the future and take 28 plus 2 and then divide that number by 5 (opposite of subtracting 2 is adding two, opposite of multiplying by five is dividing by 5).

5x-2=28 (writing it this way might also help, because now you just have to solve for x)

Black_prince [1.1K]3 years ago

3 0

2 less than (-2) 5 times a number (5x) is (=) 28 (28)
-2+5x=28
add 2 to both sides
5x=30
divide both sides by 5
x=6

the number is 6

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Solve using square roots

blsea [12.9K]

You can not see the problem

8 0

3 years ago

What are the intercepts of 2x+3y-6=30

Zolol [24]

X-Intercept is found by setting y to = 0.
<span>Y-intercept is found by setting y to =0.</span>

7 0

3 years ago

How many nonzero terms of the Maclaurin series for ln(1 x) do you need to use to estimate ln(1.4) to within 0.001?

Vilka [71]

Answer:

The estimate of In(1.4) is the first five non-zero terms.

Step-by-step explanation:

From the given information:

We are to find the estimate of In(1 . 4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)

So, by the application of Maclurin Series which can be expressed as:

$f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2 f"(0)}{2!}+ \dfrac{x^3f'(0)}{3!}+... \ \ \ \ \ --- (1)$

Let examine f(x) = In(1+x), then find its derivatives;

f(x) = In(1+x)

$f'(x) = \dfrac{1}{1+x}$

f'(0) $= \dfrac{1}{1+0}=1$

f ' ' (x) $= \dfrac{1}{(1+x)^2}$

f ' ' (x) $= \dfrac{1}{(1+0)^2}=-1$

f ' ' '(x) $= \dfrac{2}{(1+x)^3}$

f ' ' '(x) $= \dfrac{2}{(1+0)^3} = 2$

f ' ' ' '(x) $= \dfrac{6}{(1+x)^4}$

f ' ' ' '(x) $= \dfrac{6}{(1+0)^4}=-6$

f ' ' ' ' ' (x) $= \dfrac{24}{(1+x)^5} = 24$

f ' ' ' ' ' (x) $= \dfrac{24}{(1+0)^5} = 24$

Now, the next process is to substitute the above values back into equation (1)

$f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2f' \ '(0)}{2!}+\dfrac{x^3f \ '\ '\ '(0)}{3!}+\dfrac{x^4f '\ '\ ' \ ' \(0)}{4!}+\dfrac{x^5f' \ ' \ ' \ ' \ '0)}{5!}+ ...$

$In(1+x) = o + \dfrac{x(1)}{1!}+ \dfrac{x^2(-1)}{2!}+ \dfrac{x^3(2)}{3!}+ \dfrac{x^4(-6)}{4!}+ \dfrac{x^5(24)}{5!}+ ...$

$In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...$

To estimate the value of In(1.4), let's replace x with 0.4

$In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...$

$In (1+0.4) = 0.4 - \dfrac{0.4^2}{2}+\dfrac{0.4^3}{3}-\dfrac{0.4^4}{4}+\dfrac{0.4^5}{5}- \dfrac{0.4^6}{6}+...$

Therefore, from the above calculations, we will realize that the value of $\dfrac{0.4^5}{5}= 0.002048$ as well as $\dfrac{0.4^6}{6}= 0.00068267$ which are less than 0.001

Hence, the estimate of In(1.4) to the term is $\dfrac{0.4^5}{5}$ is said to be enough to justify our claim.

∴

The estimate of In(1.4) is the first five non-zero terms.

8 0

3 years ago

2D - 5F = 30 <br><br> Solve for F

Allushta [10]

Answer:

F = -6 + 2d/5

Step-by-step explanation:

2d-5f=30

subract 2D from each side

-5f=30-2d

divide both sides by -5

f= -6 +2d/5

5 0

3 years ago

Read 2 more answers

Marketing estimates that a new instrument for the analysis of soil samples will be very successful, moderately successful, or un

mylen [45]

Answer:

F(10) = P(x = 10) = 0.3

F(5) = P(x = 5) = 0.4

F(1) = P(x = 1) = 0.3

Step-by-step explanation:

Given the following :

Probability estimates given:

Very successful = 0.3

Moderately successful = 0.4

Unsuccessful = 0.3

Yearly revenue (X) :

Very successful = $10 million

Moderately successful = $5 million

Unsuccessful = $1 million

The probability mass function of X:

f(x) = probability of each valie of x

When x = 10:

F(10) = P(x = 10) = 0.3

When x = 5:

F(5) = P(x = 5) = 0.4

When x = 1:

F(1) = P(x = 1) = 0.3

5 0

3 years ago