We have the following points and their coordinates:
We must compute the distance ST between them.
The distance ST between the two points is given by:
![ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},](https://tex.z-dn.net/?f=ST%3D%5Csqrt%5B%5D%7B%28x_S-x_T%29%5E2%2B%28y_S-y_T%29%5E2_%7B%7D%7D%2C)
where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.
Replacing the coordinates of the points in the formula above, we find that:
![\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20ST%3D%5Csqrt%5B%5D%7B%28-3_%7B%7D-%28-2%29_%7B%7D%29%5E2%2B%2810_%7B%7D-3_%7B%7D%29%5E2_%7B%7D%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B1%5E2%2B7%5E2%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B50%7D%5Ctext%7B.%7D%20%5Cend%7Bgathered%7D)
Answer: ST = √50
Answer:
m=5/2
Step-by-step explanation:
the equation of slope is (y2-y1)/(x2-x1)
here are the points given: (0,5), (2,10)
let's label the points:
x1=0
y1=5
x2=2
y2=10
now substitute into the equation (m is the slope)
m=(10-5)/(2-0)
subtract
m=5/2
the slope is 5/2
Answer:
m<V = 11.2 degrees
Step-by-step explanation:
In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.
From the triangle;
UV = hypotenuse = 6.2feet
WU = opposite = 1.2feet
Required
m<V
Using the SOH CAH TOA identity
sin m<V = opp/hyp
sin m<V = WU/UV
sin m<V = 1.2/6.2
sin m<V = 0.1936
m<V = arcsin(0.1936)
m<V = 11.16
m<V = 11.2 degrees ((to the nearest tenth of a degree)
Answer:
x = y + z
=> z = y - x
Step-by-step explanation:
Hope u understand
In this question , it is given that we have a cylinder with with a radius of 9 and a surface area of approximately 791.68 units square.
The formula of surface area of cylinder is
Substituting the values of A and r, we will get
So the height of the cylinder is 5 units .
