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SCORPION-xisa [38]
2 years ago
6

PLEASE HELPPP ONG ILL GIVE YOU ALL MYPOINTS JUST HELP

Mathematics
2 answers:
vampirchik [111]2 years ago
5 0
The answer is 13 hope I helped
kvasek [131]2 years ago
3 0

Answer:

the answer is 13 :)

Step-by-step explanation:

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How is multiplying fractions the same as multiplying whole numbers and different
gtnhenbr [62]
Well one similarity is that since you have to multiply, integer rules still apply and that you can also multiply variables. A difference is that with fractions, you have to make a number into an improper fraction rather than just the regular way which would most likely be the whole number with a decimal.
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2 years ago
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A bag contains 4 oranges, 3 grapefruits, and 8 tangerines. A piece of fruit is chosen from the bag at random. What is the probab
NARA [144]
Answer is 3/15 which is simplified to 1/5 :)
7 0
3 years ago
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Factor x2+12x+35 , I appreciate all the kind generous help I can receive
stellarik [79]
So, to factor out the equation x²+12x+35, first multiply the first and last numbers.
1×35=35
So, you need to find the multiples of 35 that add up to 12.
So, you find 7 and 5. These two numbers are the magic numbers that will be used as the correct factored form of x²+12x+35, because:
>7×5=35
>7+5=12
So, using these two numbers, you get your factored form as:
(x+5)(x+7)
8 0
2 years ago
Please help !!! What’s the answer to this??
Aleksandr [31]

Answer:

Average speed is distance/time. You could say, 12/6 = 2 miles per second and say that’s the answer, but we relate to mph so much better. Since there are 60 x 60 = 3600 sec in an hour, that same speed is:

2 x 3600 = 7,200 mph

No “car” can travel this fast. Some rocket cars have gone about 1/10th this speed.

7 0
2 years ago
What are the domain and range of the real-value function f(x) =-2+√x+7
stiks02 [169]

Because the function f(x) =-2+√x+7 has √x, x should be more or equal 0.

Domain is x≥0, or [0,+∞).

The smallest value of x=0, so the smallest value of f(x) is f(0) =-2+√0+7=5,

so range is f(x)≥5, or [5, +∞).

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2 years ago
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