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3 years ago

15

Do the ratios 8/ 5 and 11 /6 form a proportion?

1 answer:

nordsb [41]3 years ago

4 0

Answer:

no they don't

hope this helps

have a good day :)

Step-by-step explanation:

You might be interested in

Decide which of the following sets of points.

Luden [163]

Answer:

Im pretty sure that the answer would be choice f.

Step-by-step explanation:

7 0

3 years ago

Forty-five percent of the 300 shoppers in a supermarket bought milk. How many of the shoppers in a supermarket bought milk?

Orlov [11]

Turn 45% into a decimal. You get 0.45, because you move the decimal two places to the left.

Then multiply 300*0.45
You get 135

135 Shoppers in the supermarket bought milk.

7 0

3 years ago

I have asked so many times and no one will answer. :(

andrew-mc [135]

Answer:

1) $\frac{1}{2^7}$ ; 2) $11^7$

Step-by-step explanation:

1) Using the Power of a Fraction Rule $(\frac{a}{b} )^x = (\frac{a^x}{b^x} )$ ,

$(\frac{1}{2} )^7 = (\frac{1^7}{2^7} )$ , which can just be simplified to $\frac{1}{2^7}$ .

2) Using the Negative Exponent Rule, $a^{-x} = \frac{1}{a^{x}}$ ,

$(\frac{1}{11} )^{-7} = \frac{1}{\frac{1}{11^7}}$ , which can be simplified to $11^7$ .

4 0

3 years ago

A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost

iris [78.8K]

Answer:

The venue has to host 47 events throughout the year

Step-by-step explanation:

Profit:

Profit is revenue subtracted by costs.

Per event:

$100,000 revenue

$50,000 costs

$100,000 - $50,000 = $50,000 profit.

If the venue wants to make a total profit margin of $2,350,000, how many events does the venue have to host throughout the year?

1 event - $50,000 profit.

x events - $2,350,000 profit.

$50000x = 2350000$

$x = \frac{2350000}{50000}$

$x = 47$

The venue has to host 47 events throughout the year

6 0

3 years ago

If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure

const2013 [10]

Answer:

$DG = 26$

$GE = 26$

$DF = 15$

$CH = 14$

$CE = 28$

Step-by-step explanation:

The figure has been attached, to complement the question.

$DE = 52$

$FC = 15$

$HE = 14$

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

$DF = FC$

$CH = HE$

$DG = GE$

Solving (a): DG

If $DG = GE$ , then

$DE = DG + GE$

$DE = DG + DG$

$DE = 2DG$

Make DG the subject

$DG = \frac{1}{2}DE$

Substitute 52 for DE

$DG = \frac{1}{2} * 52$

$DG = 26$

Solving (b): GE

If $DG = GE$ , then

$GE = DG$

$GE = 26$

Solving (c): DF

$DF = FC$

So:

$DF = 15$

Solving (d): CH

$CH = HE$

$CH = 14$

Solving (e): CE

If $CH = HE$ , then

$CE = CH + HE$

$CE = 14 + 14$

$CE = 28$

7 0

3 years ago