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Sever21 [200]
4 years ago
15

Its says use rounding or compatible numbers to estimate the sum and example 198 + 727 ans is 200+725=925 I still don't understan

d how to do it. Heres a problem 87+34 and here is one 222+203
Mathematics
1 answer:
tamaranim1 [39]4 years ago
4 0
Compatible numbers are number that are easy to add together.
If I change 87 to 90 and 34 to 30 I have compatible numbers
90 + 30 = 120.    I would probably just change the 87 to 90 since I could to 90 + 34 mentally and get 124 which is closer to the exact answer.
222 + 203 - becomes 220 +200 = 420
 May I suggest that you can also balance the numbers:  when you change 87 to 90 you added 3.  To compensate, subtract 3 from 34 and get 31.  90+31= 121, the exact answer.
222 becomes 200 so you lowered it by two. To compensate add 2 to 203.  Now you have 220+205= 425 which again, is the exact answer.  Use estimation is needed but what I just showed you works well to and give you the exact answer.
One more:  199 + 306 =   200 + 305 = 505 (exactly) Instead of 200 + 300 = 500 which is a close estimate using compatible numbers.
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4 years ago
At prestige university, the ratio of females to males is 3:1. if there are a total of 4811 students, how many are female?
Luden [163]
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The other fourth of the students are male.


5 0
3 years ago
Q6 Q15.) Which of the following four statements establishes the​ identity?
erastova [34]
A is incorrect. The identity is for the Sin( A - B). It is not for the Cos(A - B)

B is closer, but NOT the answer. The sign in the middle is incorrect, for one thing. For another Cos(pi/2) = 0,, so the answer would be cos(theta) using this formula.

C The sign is correct in C. The problem is that it is the wrong formula for Cos(theta - pi/2). C should go 
Cos(theta - pi/2) = cos(theta) cos(pi/2) + sin(theta)*sin(pi/2)

D. Looks like it's the correct answer. See the comment for C: The identity for C is actually correct for D.
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Answer D <<<<<< answer.


8 0
4 years ago
Read 2 more answers
Four consecutive multiples of 6 yield a sum of 156. What are these multiples?
olga nikolaevna [1]
Let x be the first number:
1st number: = x
2nd consecutive multiple of 6 = x+6
3rd consecutive multiple of 6 = x+12
4rth consecutive multiple of 6 = x+18
Their sum = 156 → x+(x+6)+(x+12)+(x+18) = 156
4x +30 = 156
4x = 120 and x = 30

The numbers are: 30,36,42,48
6 0
4 years ago
Read 2 more answers
2x + y = 5<br> 4x + 2y = 10
Artyom0805 [142]

Answer: x= 5-y/2

y= 5-2x

Step-by-step explanation:

2x + y= 5

4x + 2y=10

Addition of the two equations gives:

6x + 3y = 15

6x= 15- 3y

x= 15-3y/6 or simplified to x = 5-y/2

3y= 15- 6x

y= 15-6×/3 or simplified to y= 5-2x

8 0
4 years ago
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