Answer:
Step-by-step explanation:
Suppose the dimensions of the playground are x and y.
The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore, y= 780/2-3/2x. Now, the total area (A )to be fenced is
A=x*y= x*(390-3/2x)=-3/2 x^2+390x
Calculating the derivative of A and setting it equals to 0 to find the maximum
A'= -3x+390=0
This yields x=130.
Therefore y=780/2-3/2*130=195
Thus, the maximum area is 130*195=25,350ft^2
Answer:
5 hours
Step-by-step explanation:
227.5+97.5=325
325/65=5
Multiply the numerator and denominator by the whole number. you'll most likely get an improper fraction though.
Answer:
The answer to your question is 6 organisms.
Step-by-step explanation:
Data
625 ft² -------- 1 multicellular organism
3750 ft² -- number of organisms
Process
1.- To know the number of organisms that can supply 3750 ft² of lawn, we need to use proportions and cross multiplication.
625 ft² ------------------ 1 multicellular organisms
3750 ft² ------------------ x
x = (3750 x 1) / 625
x = 3750 / 625
x = 6
2.- Conclusion
3750 ft² can supply of oxygen 6 organisms.