Question

Four consecutive multiples of 6 yield a sum of 156. What are these multiples?

Answer 1

Let x be the first number:
1st number: = x
2nd consecutive multiple of 6 = x+6
3rd consecutive multiple of 6 = x+12
4rth consecutive multiple of 6 = x+18
Their sum = 156 → x+(x+6)+(x+12)+(x+18) = 156
4x +30 = 156
4x = 120 and x = 30

The numbers are: 30,36,42,48

Answer 2

Answer:

The numbers are 30,36,42,48.

Step-by-step explanation:

Given : Four consecutive multiples of 6 yield a sum of 156.

To find : What are these multiples?

Solution :

Let the first consecutive multiples of 6 be 'x'.

The second consecutive multiples of 6 be 'x+6'.

The third consecutive multiples of 6 be 'x+12'.

The fourth consecutive multiples of 6 be 'x+18'.

Now, their sum is 156

i.e. $x+(x+6)+(x+12)+(x+18) = 156$

$4x +30 = 156$

$4x = 120$

$x=\frac{120}{4}$

$x=30$

The first number is 30.

The second number is 30+6=36

The third number is 30+12=42

The fourth number is 30+18=48

Therefore, the numbers are 30,36,42,48.