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N76 [4]
3 years ago
11

The actual length (L) of a rectangle is 27 centimeters. Use the scale drawing of the rectangle to find the actual width (W).

Mathematics
2 answers:
Dominik [7]3 years ago
7 0
The ratio of the length to the width is \rm \dfrac{L}{W}.
The ratio of the sides will be the same for the scale and actual figures.

\rm \dfrac{2.4}{3.6}=\dfrac{27}{W}

I took the L/W of the scale figure
and set it equal to the L/W of the actual figure.

Now we can solve for the unknown width.
Cross-multiplication gives us this,

\rm 2.4W=3.6\cdot27

Divide by 2.4 and simplify,

\rm W=40.5

Hope that helps! :)
amid [387]3 years ago
4 0

Answer:

<h2>18 centimeters.</h2>

Step-by-step explanation:

To solve this question, we just have to use proportions. The given rectangle is showing a ratio that helps a lot to find the answer. In other words, we can use the rule of three to solve this problem.

\frac{width}{length}=\frac{2.4}{3.6}=\frac{x}{27}

Now, we solve for x:

\frac{2.4}{3.6}=\frac{x}{27}\\x=\frac{2.4(27)}{3.6}=18

Therefore, according to the proportion, the actual width is 18 centimeters.

When we use proportions and ratios like this problem, we have to make sure that we are placing magnitudes in the right order, that is, if we place width in the numerator, it always has to be in that position, placing the width in the denominator in the other ratio would be completely wrong.

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Joey likes beer and whisky and spends £75 in total on drink. His utility function for whisky (w) and beer (b) is = 5 + .
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3 years ago
Two airplanes leave an airport at the same time, the first headed due north and the second at a bearing of N42^ E . At 2:00PM, t
Leno4ka [110]

Answer:

The two airplanes are about 330miles apart.

Step-by-step explanation:

The diagram interpreting the question has been attached to this response.

As shown in the diagram,

i. the airplanes leave at point C.

ii. at 2.00pm the first and second airplanes are at points A and B respectively, where they are 312miles and 487miles away from the starting point C in directions due north and N42E from the point C.

iii. the points A, B and C form a triangle with sides a, b and c.

To solve for the value of c which is the distance between the two planes at 2.00pm, the cosine rule is used.

c² = a² + b² - 2abcosC            --------------(i)

where;

b  = 312miles

a = 487miles

C = 42°

Substitute these values into equation (i) and solve as follows;

c² = (487)² + (312)² - 2(312)(487)cos(42)

c² = (237169) + (97344) - 303888cos(42)

c² = (237169) + (97344) - 303888(0.7431)

c² = 334513 - 225819.1728

c² = 108693.8272

<em>Take the square root of both sides</em>

√c² = √108693.8272

c = 329.69

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Therefore, the two airplanes are far apart by 330miles

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3 years ago
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5 0
2 years ago
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