146*146 i will mark you the MOST brainlest PERSON on Earth

Lexi operates an orange juice stand. On Monday she used 4 bags of oranges. On Tuesday she used 1/2 as many oranges as on Monday.

Brut [27]

2 bags of oranges, 4/2=2

4 0

2 years ago

HELP ME PLEASEEEEEEEEE

Nataliya [291]

Answer:

a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

c)This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d)This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

Step-by-step explanation:

i) Which scenarios can be solved by 1.5x + 2.25 = 12.75. Select all that apply and note the given solution.

therefore 1.5x = 10.5 therefore x = 7

a) let the number be x

therefore if $\frac{3}{2} x + \frac{9}{4} = \frac{51}{4} \Rightarrow 1.5x + 2.25 = 12.75$ then the number x = 7.

This solution matches with the original equation and its solution

b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the

number of mile = x, then the number of miles Juan can ride the taxi for

$12.75 is x = 7.

This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

quarters, the number is x = 5,

$\frac{9}{4} x + \frac{3}{2} = \frac{51}{4} \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5$

This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d.) If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the

number of mile = x, then the number of miles Juan can ride the taxi for

$12.75 is x = 5.

$2.25x + 1.5 = 12.75 \Rightarrow 9x = 51 - 6 = 45 \therefore x = 5$

This solution does not match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

3 0

3 years ago

Explain the steps necessary to convert a quadratic function in standard form to vertex form

SIZIF [17.4K]

Answer:

See below.

Step-by-step explanation:

Here's an example to illustrate the method:

f(x) = 3x^2 - 6x + 10

First divide the first 2 terms by the coefficient of x^2 , which is 3:

= 3(x^2 - 2x) + 10

Now divide the -2 ( in -2x) by 2 and write the x^2 - 2x in the form

(x - b/2)^2 - b/2)^2 (where b = 2) , which will be equal to x^2 - 2x in a different form.

= 3[ (x - 1)^2 - 1^2 ] + 10 (Note: we have to subtract the 1^2 because (x - 1)^2 = x^2 - 2x + 1^2 and we have to make it equal to x^2 - 2x)

= 3 [(x - 1)^2 -1 ] + 10

= 3(x - 1)^2 - 3 + 10

= 3(x - 1)^2 + 7 <------- Vertex form.

In general form the vertex form of:

ax^2 + bx + c = a [(x - b/2a)^2 - (b/2a)^2] + c .

This is not easy to commit to memory so I suggest the best way to do these conversions is to remember the general method.

3 0

3 years ago

Read 2 more answers

What is the slope of line LM given L(9, -2) and M(3, -5)?

jasenka [17]

Answer:

1/2

Step-by-step explanation:

(y2-y1)/(x2-x1) is the equation for finding slope with two given points

-5-(-2) over 3-9 equals

-3/-6=-1/-2=1/2

7 0

3 years ago

If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t

sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 ( $6^{3}$ ), 5 groups of second power of 6 ( $6^{2}$ ), 1 group of first power of 6 ( $6^{1}$ ) and 2 groups of zeroth power of 6 ( $6^{0}$ ).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, $6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296$

This implies that $6^{4}$ exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, $6^{3}=216$ and $216\times 5=1080, 216\times 4=864$ . This implies that $216\times 5$ exceeds 1052 and thus there can be at most 4 groups of $6^{3}$ .

Then,

$1052-4\times6^{3}$

$1052-4\times216$

$1052-864$

$188$

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, $6^{2}=36$ and $36\times 5=180, 36\times 6=216$ . This implies that $36\times 6$ exceeds 188 and thus there can be at most 5 groups of $6^{2}$ .

Then,

$188-5\times6^{2}$

$188-5\times36$

$188-180$

$8$

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, $6^{1}=6$ and $6\times 1=6, 6\times 2=12$ . This implies that $6\times 2$ exceeds 8 and thus there can be at most 1 group of $6^{1}$ .

Then,

$8-1\times6^{1}$

$8-1\times6$

$8-6$

$2$

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, $6^{0}=1$ and $1\times 2=2$ . This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 ( $6^{3}$ ), 5 groups of second power of 6 ( $6^{2}$ ), 1 group of first power of 6 ( $6^{1}$ ) and 2 groups of zeroth power of 6 ( $6^{0}$ ).

Then,

$1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}$

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0

2 years ago