Answer:
oof thats hard
Step-by-step explanation:
One pair of opposite sides both parallel and congruent implies a parallelogram.
Given:

To find:
The correct equivalent equation.
Solution:
We have,

Taking sin on both sides, we get

![[\because \sin (\sin^{-1}\theta )=\theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csin%20%28%5Csin%5E%7B-1%7D%5Ctheta%20%29%3D%5Ctheta%5D)
Interchanging the sides, we get

Therefore, the correct option is 4.
Answer:
1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)
4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)
Step-by-step explanation:
To obtain the answer to the question, first let us factorise each expression. This is illustrated below:
1. 15x^7y^2 + 4x^3
Common factor is x^3, therefore the expression is written as:
x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x
Common factor is 3x, therefore the expression is written as:
3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy
Common factor is 3xy, therefore the expression is written as:
3xy(5x^6y + 2)
4. 15x^7 + 10y^2
Common factor is 5, therefore the expression can be written as:
5(3x^7 + 2y^2)