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Blababa [14]
3 years ago
13

Duncan is purchasing a home for $178,000. He makes a 15% down payment and obtains a 15 year fixed rate mortgage loan at 4% annua

l interest. His monthly payments are $1,119.15. H pays an intagible tax of 0.2%. Which of the following is the total cost of principal, interest, down payment, and amount of intagible tax? (show work)
A= $228,449.60
B= $201,447.00
C= $228,503.00
D= $201,749.60
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0
1119.15×12=13,429.8 deposits per year
cost of principal
PVAO=13,429.8×((1−(1+0.04)^(−15))÷(0.04))=149,317.72
interest
13,429.8×15−149,317.72=52,129.28
down payment
178,000×0.15=26,700
intagible tax
178,000×0.002=356

Total cost
52,129.28+356+149,317.72+26,700
=228,503....answer
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At a university, 60​% of the students who apply. Of the students the university​ accepts, 25% actually enroll If 2000 students​
sweet-ann [11.9K]

Answer:

300 students are enrolled.

Step-by-step explanation:

As the university accepts 60% of the students who apply.

As 2000 students apply, it means that:

2000 × 60% ⇒ 2000 × 0.6 = 1200 students are accepted

Out of these 1200, 25% enrolled

1200 × 25% ⇒ 1200 × 0.25 = 300 students are enrolled

Therefore, 300 students are enrolled.

5 0
2 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
3 years ago
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Contact [7]

Answer:

The answer would be -x/3x^6

Step-by-step explanation:

The first step that you should take is apply the fraction rule.

That would make it -1/3/x^6

Then apply the fraction rule again.

That would make it. 1/3/-x^6

Then apply the last fraction rule.

That would make it -1/3x^6

5 0
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Inga [223]

Answer:4) t+uv

Step-by-step explanation:

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