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Sophie [7]
3 years ago
12

61 random samples of city rent prices are selected from a normally distributed population the samples have a mean of $738 and a

standard deviation of $41 construct a 95% confidence interval for the population standard deviation
Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

(728, 748)

Step-by-step explanation:

You need the Z value which for 95% confidence interval is 1.96. The mean is $738 and the standard deviation of $41.

X-Zs/\sqrt{n} \\ X+Zs/\sqrt{n}

Therefore we can calculated the confidence interval

738-1.96\cdot{41}/\sqrt{61} =738-10.3

738±10.3

The interval is (728,748)

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