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Ulleksa [173]
3 years ago
15

ANSWER ROGHT AWAY!!!!!!!​

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0
X>4 because 4*7=28 so therefore x would just have to be greater than 4
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The product of -5 and the sum of X and eight decreased by the product of three and X
Alla [95]
-5(x+8)-3x

simplified would be
-8x-40
5 0
3 years ago
For some reason it says square but please help! I need to know step by step what to do.
quester [9]

Answer:

8.06 inches

Step-by-step explanation:

The diagram shows a rectangle with width of 4 inches and area of 28 square inches.

Use area formula:

A_{\text{rectangle}}=\text{Width}\times \text{Length}

So,

28=4\times \text{Length}\Rightarrow \text{Length}=\dfrac{28}{4}=7\ \text{inches}

By the Pythagorean theorem,

\text{Diagonal}^2=\text{Width}^2+\text{Length}^2\\ \\\text{Diagonal}^2=4^2+7^2\\ \\\text{Diagonal}^2=16+49\\ \\\text{Diagonal}^2=65\\ \\\text{Diagonal}=\sqrt{65}\approx 8.06\ \text{inches}

7 0
3 years ago
Round 0.641 to the nearest hundredth. ​
mixas84 [53]

Answer:

0.64

Step-by-step explanation:

Find the number in the hundredth place  4  and look one place to the right for the rounding digit  1 . Round up if this number is greater than or equal to  5  and round down if it is less than  5 .

4 0
4 years ago
Solve n^4-11n^2+30÷n^4-7n^2+10
Morgarella [4.7K]
Factor the numerator and denominator...

(n^4-5n^2-6n^2+30)/(n^4-2n^2-5n^2+10)

[n^2(n^2-5)-6(n^2-5)]/[n^2(n^2-2)-5(n^2-2)]

[(n^2-5)(n^2-6)]/[(n^2-5)(n^2-2)]  notice the (n^2-5)s cancel out

(n^2-6)/(n^2-2)  

We could further factor this because each is a difference of squares to:

[(n+√6)(n-√6)]/[(n+√2)(n-√2)
8 0
3 years ago
Deena is planting two rectangular gardens. One garden is 3.67 feet by 8.56 feet, and the other garden is 3.67 feet by 7.45 feet.
Finger [1]

Answer:

A is the correct expression

Step-by-step explanation:

the formula for area of a rectangle is A=WxL

A=area W=width L=length

8.56x3.67=31.42 area of first garden

7.45x3.67=27.34 area of second garden

<em>hope this helps!</em>

<em>have a great day :)</em>

3 0
4 years ago
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