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atroni [7]
3 years ago
10

Which functions have a horizontal asymptote? Y = f(x) y = h(x) y = g(x) y = k(x) On a coordinate plane, 4 exponential functions

are shown. Y = f (x) approaches the x-axis in quadrant 1 and increases exponentially in quadrant 2. It goes through (0, 1) and (negative 4, 5). Y = g (x) approaches the x-axis in quadrant 1 and increases exponentially in quadrant 2. It goes through (0, 1) and (negative 1, 3). Y = h (x) approaches the x-axis in quadrant 2 and increases exponentially in quadrant 1. It goes through (0, 1) and (1, 3). Y = k (x) approaches the x-axis in quadrant 2 and increases exponentially in quadrant 1. It goes through (0, 1) and (4, 5).
Mathematics
2 answers:
nignag [31]3 years ago
8 0

Answer:

all of them

Step-by-step explanation:

all have asymptote

Fed [463]3 years ago
5 0

Answer:

Is all of them !!

Step-by-step explanation:

Because they all have asymptote

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What are the roots of the quadratic equation x2+2x=-5
stiks02 [169]

Answer:

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Step-by-step explanation:

Write the equation in standard form to find the roots, also known as the solutions, zeros, or x-intercepts, of the quadratic.

x² + 2x + 5 = 0

Use the quadratic formula by substituting a= 1, b = 2 and c = 5.

x = \frac{-2 +/- \sqrt{(-2)^2 - 4(1)(5)} }{2(1)} = \frac{-2 +/-\sqrt{4 -20 } }{2} = \frac{-2 +/-\sqrt{-16 } }{2} = \frac{-2 +/-4i }{2} = -1 +/-2i

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There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

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Step-by-step explanation:

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Read 2 more answers
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