Multiply. write your answer as a fraction in simplest form What is 4 over 9 of 36

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

Answer:

Step-by-step explanation:

$\dfrac{4}{9}\ of\ 36\to\dfrac{4}{9}\cdot36=\dfrac{4\cdot36\!\!\!\!\!\diagup^4}{9\!\!\!\!\diagup_1}=\dfrac{4\cdot4}{1}=\dfrac{16}{1}=16$

You might be interested in

Functions math, please help

kolbaska11 [484]

Answer:

Slope: 2

Y-intercept: (0,-7)

4 0

3 years ago

Read 2 more answers

James has $5.00 more than three times what Catherine has. Together they have $41.00. How much does each student have?

Tpy6a [65]

Hey.

acc'g to the conditions :

Let Catherine has x
and James has 5 + 3x

Then,

$5 + 4x = 41 \\ \\ \implies 4x +5 -5 = 41-5 \\ \\ \implies 4x = 36 \\ \\ \implies x= \dfrac{36}{4} \\ \\ \implies x = 9$

Hence

• Catherine has = x = $9,
• and James has = 5 +3x = 5 + 3(9) = $32

Thanks.

7 0

3 years ago

If a wall is in a 1/4 in scale drawing is 6 in tall how tall is the actual wall

vekshin1

So 1/4
that measn that the scale wall is 6 inches while the real wall is 4 times 6=24 inches tall (logically, it would be something like 1in/4ft so it woul dbe 24 feet not 24 inches but ok)

so 1/4
6 inches scale drawing is 1/4 of real wall
6=1/4 real
multiply by 4
24=real

asnwer is 24 inches

6 0

3 years ago

Choose the equation that could be used to solve this problem.

olganol [36]

23 is the number the answer is c

8 0

3 years ago

Read 2 more answers

The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor

nadya68 [22]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16$

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: