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Alex17521 [72]
3 years ago
10

What is the simplest form of 2(4x+y)+3(x-6y)+x^2​

Mathematics
2 answers:
kipiarov [429]3 years ago
7 0

Answer:

8x+2y+3x-18y+x^2

final answer: x^2+11x-16y

*edited*

OverLord2011 [107]3 years ago
7 0
(For full answer you might have to go to the comments)

Answer: 11x-16y+x^2

Step By Step:

1. Expand
8x+2y+3(x-6y)+x^2
((^ MEANS EXPONENTS OR TO THE POWER OF))

2. Expand
8x+2y+3x−18y+x^2

3. Collect like terms
(8x+3x)+(2y-18y)+x^2

4. Simplify
11x-16y+x^2
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Answer:

Step-by-step explanation:

the shape looks like a cube.. and maybe they say something about that outside of the picture, even but assuming that it is a cube, we know all the sides are the same.

we also know that the area of one side of the cube is  3 \frac{1}{4}

so multiply that  

W x L = area

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10 \frac{9}{16}  = area

10.5625 = area

those two answer above are the same .. just one is in fractions and one is in decimals

there are 6 sides on a cube, so multiply the above answer by 6

6* answer = 63.375

63 \frac{3}{8}  ( this is your answer)

both of those are also identical , but look different for the reasons I mentioned above

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Answer:

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x^2 - 5x-14 = 0

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3 years ago
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Step-by-step explanation:

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3 years ago
43. Can you place ten lumps of sugar in three empty cups so that
erma4kov [3.2K]

Answer: No.

Step-by-step explanation:

We have 10 lumps of sugar, and we want to divide them into 3 cups, in such a way that there is an odd number of lumps in each cup.

This only can happen if we have 3 odd numbers such that the addition is equal to 10.

Now 10 is an even number, remember that even numbers can be written as:

2*k

where k is an integer number.

And odd numbers can be written as:

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where n is an integer.

Then we have 3 odd numbers, let's call them:

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Now let's add them:

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2*(n + k + p) + 2 + 1 =

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So for any 3 odd numbers that we add together, the result will always be an odd number.

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Then is not possible to have an odd number of lumps in each cup.

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3 years ago
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