Simplify (x1/2) 1/6 • x1/3 •x1/4 •x1/12 •x2/3

a local parts shop buys a machine that costs $500,000. its value depreciates exponentially each year by 10%. what is the machine

jeka94

Hello!

Answer:

$295.295

Explanation:

Of the statement, we have that the price of the machine decreased 10% every year exponentially, so in the first year it real value drops to 90% of the costs. For 5 years, It can be expressed and simplified by the following equation:

We can't use that the percent drop as a percent itself, so we are going to divide 90% by 100%, and it will give us an entire number.

$\frac{90}{100}=0,9 \\ \\ Value=Costs.(0.9)^{years}$

By substituting we have:

$Value=500000.(0.9)^{5}$

Value: $295.245

Have a nice day!

8 0

3 years ago

The line y=2/5x +7 is dilated by a scale factor of 4 centered at the point (5,9). What equation represents the image of the lone

Serjik [45]

Answer:

Step-by-step explanation:

I don’t understand

7 0

3 years ago

What is the amplitude of the graph of

Lera25 [3.4K]

It is 2 :)
Y=A sin(B(x+C))+D

Where A is equal to the amplitude.

Would appreciate brainliest answer :)

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{

il63 [147K]

Answer:

$\frac{x-3}{2x-3}$ . hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

$x^2-5x+6$

Now let's find what ac is (it's just c since a=1...)

$AC= 6$

List factors of -6

$\pm1, \pm2, \pm3, \pm6$ .

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

$(x-2)(x-3)$

Ok now let's factor the second equation:

$2x^2-7x+6$

Multiply a and c

$AC = 12$

List factors of 12:

$\pm1, \pm2, \pm3, \pm4, \pm6, \pm12$ .

Factors that add up to -7 and multiply to 12:

$-3\ and\ -4$

Rewrite equation:

$2x^2-4x-3x+6$

Group terms:

$(2x^2-4x)+(-3x+6)$

Factor out GCF:

$2x(x-2)-3(x-2)$

Rewrite:

$(2x-3)(x-2)$

Now let's write out the equation using these factors:

$\frac{(x-2)(x-3)}{(2x-3)(x-2)}$ .

Here we can factor out the x-2 and the simplified form is:

$\frac{x-3}{2x-3}$

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0

2 years ago

I need help plz in opt math..plzz

jeka94

Answer:

the value of y=2

here ,

(2x-1,3y-2)=(x+2,2y)

then,

3y-2=2y{corresponding elements}

3y-2y=2

or, y=2

hence the value of y=2

8 0

3 years ago

Read 2 more answers