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1 year ago

Simplify (x1/2) 1/6 • x1/3 •x1/4 •x1/12 •x2/3

Mathematics

1 answer:

Vinvika [58]1 year ago

8 0

Cheack the expononets may be it wrong harder to get

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g100num [7]

An application for employment

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3 years ago

Jason is throwing a pizza party.He has 4/18 pounds of cheese available and he needs 3/8 pounds of cheese to make a pizza. How ma

Bess [88]

Step-by-step explanation:

It is given that,

Jason has 4/18 pounds of cheese available and he needs 3/8 pounds of cheese to make a pizza.

Let he can make x pizzas. It can be calculated by dividing 4/18 by 3/8 such that,

$x=\dfrac{4/18}{3/8}\\\\=\dfrac{4}{18}\times \dfrac{8}{3}\\\\=0.592$

x = 0.6

So, he can make 0.6 part of the pizza.

3 0

2 years ago

You have 6 donuts and you want to give 2/3 of them to a friend and keep 1/3 for yourself. How many donuts would your friend get?

Furkat [3]

4 donuts because you can change the denominator to 6 and get 4/6 and thats how you get 4

3 0

3 years ago

Read 2 more answers

Find the diameter of a circle whose circumference is 74cm

jenyasd209 [6]

Answer:

≈ 24 cm

Step-by-step explanation:

Hi there !

c = 2πr } => c = πd => d = c/π

2r = d

replace c ; π

π =3.14

d = 74cm/3.14

= 23.5668

≈ 24 cm

Good luck !

4 0

3 years ago

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago