"We keep tossing a fair coin n = 10^6 million times, write down the outcomes: it gives a Heads-and-Tails-sequence of length n. W
e call an integer i special, if the i, i + 1, i + 2, i + 3, . . . , i + 18-th elements of the sequence are all Heads. That is, we have a block of 19 consecutive Heads starting with the i-th element of the sequence. Let X denote the number of special integers i. What is the expected value of X? I also want the numerical value. 5. We rand
1 answer:
Answer:
Check the explanation
Step-by-step explanation:
Let be the indicator random variable that takes the value 1 if the ith coin is the first coin in a sequence of 19 consecutive heads.
For any sequence of length 19, the starting coin can be from toss i ,
such that i is between 1 and n - 19+1
Thus the number of such sequences is
Kindly check the attached image below for the step by step explanation to the question above.
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Answer:
Yes; she will have $4008 for other expenses.
Step-by-step explanation:
First you find out how much she saved by multiplying 350 by 36 as she saved for 3 years which is 36 months.
After that you need to work out the amount she needs in total for her tuition by multiplying 4 by 3723 which is the amount needed per year.
If her parents add to her account half the amount she saved that means that they give her an additional 6300 as that's half of 12600.
This means she has 18900 and if you take away 14892 you will be left with 4008 for expenses.
Answer:
B and F
Step-by-step explanation:
Given
x² + 4x + 4 = 12 ( subtract 4 from both sides )
x² + 4x = 8
Using the method of completing the square to solve for x
add ( half the coefficient of the x- term )² to both sides
x² + 2(2)x + 4 = 8 + 4, that is
(x + 2)² = 12 ( take the square root of both sides )
x + 2 = ± ( subtract 2 from both sides )
x = ± - 2
= ± 2 - 2
Hence
x = 2 - 2 → B
x = - 2 - 2 → F