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3 years ago

The graph shows the function f(x) = 2* What is the value of xwhen f(x) = 8?

Mathematics

2 answers:

White raven [17]3 years ago

7 0

Answer:

A. 3

Step-by-step explanation:

y = 2^x

y = 8

Plug y as 8 in the first equation.

8 = 2^x

Make the left side of the equation with a base of 2.

2^3 = 2^x

Cancel bases.

3 = x

soldi70 [24.7K]3 years ago

3 0

Answer:

x=3

Step-by-step explanation:

f(x) = 2^x

Let f(x) =8

8 = 2^x

Rewriting 8 as 2^3

2^3 = 2^x

The bases are the same so the exponents are the same

3=x

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The table below shows the price in dollars for the number of roses indicated is the price proportional to the number of roses ex

makvit [3.9K]

Answer:

Price of roses is proportional to the number of roses.

Step-by-step explanation:

Let the price of roses are proportional to the number of roses.

Equation representing this phenomenon will be,

P = k(R) ⇒ k = $\frac{P}{R}$

where 'P' = price of the roses

R = Number of roses

k = Proportionality constant

If we substitute the values of P and R and we get the same value of constant 'k', then the equation will be true.

For R = 3 and P = $9

k = $\frac{9}{3}$

k = 3

For R = 6 and R = 18

k = $\frac{18}{6}$

k = 3

K is same in both the conditions, therefore, Price of roses are proportional to the number of roses.

6 0

2 years ago

I need help on this

Evgen [1.6K]

Answer:

the last one talking about victoria has y dollars

Step-by-step explanation:

x times 12 is equal to y, so the equation is y = 12x

6 0

2 years ago

Read 2 more answers

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$