Answer:
Mode
Step-by-step explanation:
Mean:
Before replacing = 464/8 = 58
After replacing 42 with 98 = 520/8 = 65
Mode:
Before replacing = 42
After replacing 42 with 98 = 98
Median:
25, 42 , 42 , 47, 55 , 59, 96,98
Before replacing = 47+55/2 = 51
25, 42 , 47, 55 , 59, 96,98 , 98
After replacing 42 with 98 = 55+59/2 = 114/2 = 57
D : 0.300- 0.006 is correct
A is wrong bec 0.3 doesn’t have the extra 0’s in the end
B is wrong bec the decimal places aren’t aligned
C is wrong bec again, the decimal places aren’t aligned
Steps to solve:
7 = 11t
~Divide 11 to both sides
7/11 = 11t/11
~Simplfy
7/11 = t
The fraction can't be simplified any further.
Best of Luck!
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.