Answer:
A = X+X+2+X+4=3X+6 =(X+1)+(X+2)+(X+3)
B = 3X+6 =(X+1)+(X+2)+(X+3)
C = not (3X+3)
D = not (3X+3)
The anwser to your question is 1 and 5/7
Lines that are parallel have the same slope, and the given line (y = 6x - 5) has a slope of 6; we are looking for a line with a slope of 6.
To form an equation for a line, you need to know the y-intercept (the point at which the line intersects the y-axis). The first step to finding the y-intercept is to plot the given point. After you've done that, count six units up (this is our slope) and one to the right; plot the point. Lastly, draw the line by connecting the points and see where the line intersects the y-axis.
My graph shows that the line intersects the y-axis at -17. All that's left now is to put our information together into an equation. I'm assuming the problem wants the equation in slope-intercept form; slope-intercept form is y = mx + b where m is the slope and b is the y-intercept, so it would look like this:
y = 6x -17
Hope this helps.
X=8
Set up proportions would give you: 10/3x+1 = 22/7x-1
With that in mind, cross multiply, which would give you: 10(7x-1) = 22(3x+1).
Turns into: 70x -10 = 66x+22. Then just solve for x
Answer:
x = -4
Step-by-step explanation:
x+y = -10 -------- (1)
x-y = 2 ------- (2)
from (1)
x+y = -10
y = -10-x -------- (3)
substitute (3) into (2)
x-y = 2
x-(-10-x) = 2
x+10+x = 2
2x = 2-10
2x = -8
x = -8/2
x = -4
