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dsp73
3 years ago
13

I. Write the answer with the proper label. ( 2 pts each)

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0
S = D/t
120 = D / 0.5
D = 120*0.5
D = 60 km

S = D/t
70 = D / 2.5
D = 70*2.5
D = 175 miles
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Write the fraction 7/16 and 193/1000 as decimal then compare the values
givi [52]
7/16=0.4375
193/1000=0.193
0.4375 is bigger than 0.193 by 0.2445
3 0
3 years ago
A club raises $3,207 to buy stuffed animals for a local children's hospital. Each stuffed animal costs $17. What is the maximum
Ksju [112]

Answering:

188

Explaining:

To solve this problem, we must divide the total amount of money raised by the cost of the stuffed animals. Each stuffed animal costs $17. The club raised $3,207 to buy said stuffed animals. By dividing the money earned, which is also the money the club is able to spend, by the cost of a single/one stuffed animal, we will get how many stuffed animals the club can purchase with the money they currently possess. Our equation will look like this: 3,207 ÷ 17.

After dividing 3,207 by 17, we have the number 188.64705882. This can be rounded to the nearest tenth to create the simpler yet still accurate number 188.6.

Our final step is to round 188.6 down to the whole number it already has. (That is to say, simply cut off the fraction and remove it to get our answer.) This step must be done because we are buying stuffed animals in a real-world situation. The club would not be able to purchase part of a stuffed animal for a fraction of the cost, and the cost of the stuffed animals in the problem is a fixed value. This means that the fraction is irrelevant since we cannot purchase anything with it, effectively making it totally irrelevant to the answer. After removing the fraction from 188.6, we are left with 188.

Therefore, the maximum number of stuffed animals the club can buy is <em>188 stuffed animals</em>.

4 0
3 years ago
Please help i’m so confused
Viktor [21]

Answer:−x+6

x

Step-by-step explanation:

8 0
3 years ago
Simplify negative 2 and 1 over 9 – negative 4 and 1 over 3
iren2701 [21]
Ok to start you have to put


2+-1/9 - 4+-1/3

 what exactly is the question because without the proper info. nobody is going to be able to figure it out.
5 0
3 years ago
Read 2 more answers
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

6 0
3 years ago
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