f(x) = 2x^2 - x - 10
Part A:
x-intercepts: (-2,0), (5/2,0)
Part B:
The vertex is the minimum
vertex: (1/4, -81/8)
Part C:
A:
x: -2, -1, 1/4, 1, 2
y: 0, -7, -81/8, -9, -4
B:
It's a little hard to see, but I'm almost positive the y intercept is -1.
Remember, the y intercept is wherever the line intercepts in the y axis 0.
Good luck my man.
Answer:
7.7142
Step-by-step explanation:
Y=10x+1
x=-1→y=10(-1)+1=-10+1→y=-9
x=0→y=10(0)+1=0+1→y=1
x=1→y=10(1)+1=10+1→y=11
x=5→y=10(5)+1=50+1→y=51
x y
-1 -9
0 1
1 11
5 51
Answer:a) L.C.M OF 2,3,5 is 30
THEREFORE=60/30+15/30÷10/30-6/30
=60/30+15/30×30/10-6/30(DMAS)
=60/30+3/2-6/30
=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.
=105/30-6/30
=105-6/30
=99/30
=33/10
b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3