Answer:
y = 2/3x - 5 or in standard form 3y = 2x - 5
Step-by-step explanation:
Remember this fact: Parallel lines have the same slope
Step 1 Solve for y so that the equation is in the slope- intersect form
2x - 3y = 6
-3y = -2x + 6
-3y/-3 = -2x/-3 + 6/-3
y = 2/3 x -2
now we know the slope is 2/3 or
when the equation is in Standard form Ax + By = C you can use this fact: slope = - A/B so the slope = -2/-3 = 2/3
Remember the Parallel lines have the same slope
Find the y-intersect "b" use the slope = 2/3 and point (6, -1)
y = mx + b
-1 = 2/3(6) + b
-1 = 4 + b
-5 = b
Now write the equation of line that is parallel to the given line and passes through point (6, -1)
y = 2/3x - 5 or in standard form 3y = 2x - 5
Answer:
Step-by-step explanation:
3. the answer should be -68
5.-8.97
Answer:
y = -1/8 x² + 5
Step-by-step explanation:
Parabola opens vertically and vertex (h,k) = (0,5), pass point (4,3)
basic formula: y = a(x - h)² + k
y = a (x-0)² + 5
y = ax² + 5 pass (4,3)
3 = 16a + 5
a = (3-5)/16 = -1/8
equation: y = -1/8 x² + 5
check: pass another point (-4,3)
-1/8 * (-4)² + 5 = -2 + 5 = 3
Cos 18 = x/25
x = 25 cos 18
x = 25(0.9510) = 23.775 ~ 23.78 cm
Answer: x1 = 5
x2 = 1
Step-by-step explanation:
1. Identify the coefficients
2. Move the constant to the right side of the equation and combine
3. Complete the square
4. Solve for x
