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DaniilM [7]
3 years ago
5

9+3.5g=11-0.5g9+3.5g=11−0.5g

Mathematics
2 answers:
Zanzabum3 years ago
6 0

Answer:

Step-by-step explanation:

mina [271]3 years ago
5 0

g = 0.5

Step-by-step explanation:

Based on my observation, the exact question is

9 + 3.5g = 11 - 0.5g

Here, we need to find the value of g. For that, combine the same variables on a side.

Therefore,

9 + 3.5g = 11 - 0.5g

3.5g + 0.5g = 11 - 9

4g = 2

g = 2/4

g = 0.5

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Step-by-step explanation:

By replacing the points in the current equation you can get true statements which are correspondent to answer A,B,D

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1 year ago
It costs deirdre $212 to make candles. how many candles must she sell at $8 apiece to make a profit?
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In the diagram, the length of segment BC is 23 units,
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Answer:

The length of segment DC 33 units.

Step-by-step explanation:

Given:

The length of segment BC is 23 units.

To find:

Length of segment DC=?

Solution:

AB = 2x + 7

From the figure ,AB = BC

2x + 7 = 23

2x = 23 - 7

2x = 16

x = 8

In the Δ ABD and ΔCBD

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(2) ∠DBA = ∠DBC = 90°

(3) BD = BD(Common side of both the triangle.)

Thus by using SAS congurence property .

Δ ABD ≅ ΔCBD

Thus AD = DC(Corresponding sides of the congurent triangle.)

Thus AD = 4x + 1

Substituting  x = 8

AD = 4 \times 8 + 1

AD = 32 + 1

AD    = 33 unit

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5 0
3 years ago
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Reagan has a rectangular bedspread that measures 238 centimeters by 435 centimeters. She wants to sew a fringe around the edge o
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Step-by-step explanation:

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3 years ago
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Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo
NNADVOKAT [17]

Answer:

a

  P(a | e') =  0.22

  P(b | e') =  0.28

  P(c | e') =  0.33

b

  P(a | e' , d' , b') = 0.57

Step-by-step explanation:

From the question we are told that

   The probabilities are

Supplier  chosen            A                     B                    C            

Probability                P(a) = 0.20       P(b) =  0.25   P(c) =  0.15      

                                       D                      E

                                P(d) =  0.30     P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(a | e') =  \frac{P (a \  and \  e')}{P(e')}

      P(a | e') =  \frac{P (a)}{P(e')}

     P(a | e') =  \frac{P (a)}{1- P(e)}

=>   P(a | e') =  \frac{ 0.20}{1- 0.10}

=>   P(a | e') =  0.22

Generally the new probability of companies B  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(b | e') =  \frac{P (b \  and \  e')}{P(e')}

      P(b | e') =  \frac{P (b)}{P(e')}

     P(b | e') =  \frac{P (b)}{1- P(e)}

=>   P(b | e') =  \frac{ 0.25}{1- 0.10}

=>   P(b | e') =  0.28

Generally the new probability of companies C  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(c | e') =  \frac{P (c \  and \  e')}{P(e')}

      P(c | e') =  \frac{P (c)}{P(e')}

     P(c | e') =  \frac{P (c)}{1- P(e)}

=>   P(c | e') =  \frac{ 0.15}{1- 0.10}

=>   P(c | e') =  0.17

Generally the new probability of companies D  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(d | e') =  \frac{P (d \  and \  e')}{P(e')}

      P(d | e') =  \frac{P (d)}{P(e')}

     P(d | e') =  \frac{P (d)}{1- P(e)}

=>   P(d | e') =  \frac{ 0.30}{1- 0.10}

=>   P(c | e') =  0.33

Generally the probability that  B, D , E  are not chosen this year is mathematically represented as

      P(N) =  1 - [P(e) +P(b) + P(d) ]

=>       P(N) =  1 - [0.10 +0.25  +0.30 ]

=>       P(N) =  0.35

Generally the probability that A is chosen given that E , D , B  are rejected this year is mathematically represented  as

      P(a | e' , d' , b') =  \frac{P(a)}{P(N)}

=>     P(a | e' , d' , b') =  \frac{0.20 }{0.35 }    

=>     P(a | e' , d' , b') = 0.57

5 0
3 years ago
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