Answer:
93.32% probability that a randomly selected score will be greater than 63.7.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 80.2, \sigma = 11](https://tex.z-dn.net/?f=%5Cmu%20%3D%2080.2%2C%20%5Csigma%20%3D%2011)
What is the probability that a randomly selected score will be greater than 63.7.
This is 1 subtracted by the pvalue of Z when X = 63.7. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{63.7 - 80.2}{11}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B63.7%20-%2080.2%7D%7B11%7D)
![Z = -1.5](https://tex.z-dn.net/?f=Z%20%3D%20-1.5)
has a pvalue of 0.0668
1 - 0.0668 = 0.9332
93.32% probability that a randomly selected score will be greater than 63.7.
2,320,502 <=== Two million, three-hundred and twenty thousand five hundred and two
Mukat gets 40, Usha gets 8
Step-by-step explanation:
Mukat = 5 × Usha
After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)
Then Mukat = final number of books for Usha
5 × Usha - 16 = Usha + 16
(5 × Usha ) - Usha = 16+16
4 × Usha = 32
Usha = 8 i.e her number of books.
Mukat = 5×8=40.
I HOPE IT'S OK
The volume is 905.32 i believe
12(12)=144, 144(3.14)=452.16, 452.16(6)=2712.96, 2712.96/3=904.32
<h2>
Answer:</h2>
please see analysis
<h2>
Step-by-step explanation:</h2>
F
![(SSS\ Congruence\ Postulate)](https://tex.z-dn.net/?f=%28SSS%5C%20Congruence%5C%20Postulate%29)
![2.\ { \triangle\ CAT\cong { \triangle\ BED\ \left\{\right.Given\left.\ \right\}](https://tex.z-dn.net/?f=2.%5C%20%7B%20%5Ctriangle%5C%20CAT%5Ccong%20%7B%20%5Ctriangle%5C%20BED%5C%20%5Cleft%5C%7B%5Cright.Given%5Cleft.%5C%20%5Cright%5C%7D)
![\bar{AT}\cong\bar{ED}](https://tex.z-dn.net/?f=%5Cbar%7BAT%7D%5Ccong%5Cbar%7BED%7D)
![\overline{AT}=20](https://tex.z-dn.net/?f=%5Coverline%7BAT%7D%3D20)
![so\ \overline{ED}=20](https://tex.z-dn.net/?f=so%5C%20%5Coverline%7BED%7D%3D20)
![DE=3x-7=20\rightarrow\ x=9](https://tex.z-dn.net/?f=DE%3D3x-7%3D20%5Crightarrow%5C%20x%3D9)
<em>I hope this helps you:)</em>