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lana66690 [7]
3 years ago
12

Jacky baked some biscuits.he kept 3/7 of the biscuits in container A.5/8 of the remainder in container B and rest in container C

there were 168 more biscuits in container A than in container C.how many biscuits dud Jacky bake?
Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0
Let "b" represent the number of biscuits Jacky baked.
.. container A holds (3/7)b
.. container B holds (1 -3/7)*(5/8)b = (5/14)b
.. container C holds (1 -3/7 -5/14)b = (3/14)b = 168

Then
.. b = 168/(3/14) = 784

Jacky baked 784 biscuits.
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<u>Step-by-step explanation:</u>

Use elimination method.  Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable.  <em>I will be eliminating y</em>

6x +  y =  15    → 2(6x +  y =  15)   →   12x + 2y = 30

-7x - 2y = -10   → 1(-7x + 2y = -10)   →  <u> -7x - 2y = -10</u>

                                                             5x        = 20

                                                               x         =  4

Next, replace "x" with "4" into either equation and solve for y.

6(4) + y = 15

24  + y = 15

         y  = -9


<u>Check:</u>

Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.

-7x - 2y = -10

-7(4) - 2(-9) = -10

-28  -   -18  = -10

-28  +  18 = -10

       -10    =  -10  \checkmark

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Step-by-step explanation:

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