1. y= 6
2. y= 12
3. y=18
4. y= 24
5. y=5
6. y= 10
7. y=15
8. y= 20
9. y=0
10. y= 0.2
11. y=0.4
12. y=0.6
Hope this helps!
<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer:
Step-by-step explanation:
Let's write a system of equations. I'm going to call them w, x, y, and z.
w = 4x (because m∠1 is 4 times m∠2)
w + x = 90 (bc ∠1 and ∠2 are complementary, meaning they add up to 90)
w = y (bc ∠1 and ∠3 are vertical angles, meaning they are equal)
y + z = 180 (bc ∠3 and ∠4 are supplementary, meaning they add up to 180)
When we substitute w=4x into the second equation, we get 5x=90 → m∠2 = 18°. Since w=4x, m∠1 = 18*4 = 72°. Since w=y, m∠3 = 18°. Finally, because y+z=180, m∠4 = 180-18 = 162°. Hope this helps!
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