Given that,
Energy ![H=2.7\times10^{31}\ W](https://tex.z-dn.net/?f=H%3D2.7%5Ctimes10%5E%7B31%7D%5C%20W)
Surface temperature = 11000 K
Emissivity e =1
(a). We need to calculate the radius of the star
Using formula of energy
![A=\dfrac{H}{e\sigma T^4}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7BH%7D%7Be%5Csigma%20T%5E4%7D)
![4\pi R^2=\dfrac{H}{e\sigma T^4}](https://tex.z-dn.net/?f=4%5Cpi%20R%5E2%3D%5Cdfrac%7BH%7D%7Be%5Csigma%20T%5E4%7D)
![R^2=\dfrac{H}{e\sigma T^4\times4\pi}](https://tex.z-dn.net/?f=R%5E2%3D%5Cdfrac%7BH%7D%7Be%5Csigma%20T%5E4%5Ctimes4%5Cpi%7D)
Put the value into the formula
![R=\sqrt{\dfrac{2.7\times10^{31}}{1\times5.67\times10^{-8}\times(11000)^4\times 4\pi}}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7B%5Cdfrac%7B2.7%5Ctimes10%5E%7B31%7D%7D%7B1%5Ctimes5.67%5Ctimes10%5E%7B-8%7D%5Ctimes%2811000%29%5E4%5Ctimes%204%5Cpi%7D%7D)
![R=5.0\times10^{10}\ m](https://tex.z-dn.net/?f=R%3D5.0%5Ctimes10%5E%7B10%7D%5C%20m)
(b). Given that,
Radiates energy ![H=2.1\times10^{23}\ W](https://tex.z-dn.net/?f=%20H%3D2.1%5Ctimes10%5E%7B23%7D%5C%20W)
Temperature T = 10000 K
We need to calculate the radius of the star
Using formula of radius
![R^2=\dfrac{H}{e\sigma T^4\times4\pi}](https://tex.z-dn.net/?f=R%5E2%3D%5Cdfrac%7BH%7D%7Be%5Csigma%20T%5E4%5Ctimes4%5Cpi%7D)
Put the value into the formula
![R=\sqrt{\dfrac{2.1\times10^{23}}{1\times5.67\times10^{-8}\times(10000)^4\times4\pi}}](https://tex.z-dn.net/?f=R%3D%5Csqrt%7B%5Cdfrac%7B2.1%5Ctimes10%5E%7B23%7D%7D%7B1%5Ctimes5.67%5Ctimes10%5E%7B-8%7D%5Ctimes%2810000%29%5E4%5Ctimes4%5Cpi%7D%7D)
![R=5.42\times10^{6}\ m](https://tex.z-dn.net/?f=R%3D5.42%5Ctimes10%5E%7B6%7D%5C%20m)
Hence, (a). The radius of the star is ![5.0\times10^{10}\ m](https://tex.z-dn.net/?f=5.0%5Ctimes10%5E%7B10%7D%5C%20m)
(b). The radius of the star is ![5.42\times10^{6}\ m](https://tex.z-dn.net/?f=5.42%5Ctimes10%5E%7B6%7D%5C%20m)
(a). By the inertia, it's difficult to stop heavier mass than lighter mass.
As, moment of inertia is directly proportional to the mass of the body.
Thus, more force is required to stop the boy with heavier mass than lighter mass.
The problem statement for the given case is,
The time taken by the heavier body to stop swinging is more than the lighter body, then what is the impact of weight on the time period of the swing?
Answer:
2.00m
Explanation:
All we need to do to find the wavelength of the first intereference maximum is subtract both values we are given.
8.00 - 6.00 = 2.00m
Best of Luck!