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ivann1987 [24]
3 years ago
5

For physics show-and-tell, you want to impress the class by sipping water through a long straw. If you hold the straw vertically

, determine the length of the longest straw that you could, in principle, drink from in this manner._____ mAdditional Materials Show My Work (Optional)
Physics
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

10.31 m

Explanation:

To find the result you have to use the formula: h = p / eg.

Where: e = 1000Kg/m^3          g=9.8m/s^2     p= 1.01 * 10^5 Pa

The calculation will be:

h= 1.01 * 10^5 / (1000kg/m^2) * (9.8m/s^2)

h= 10.31 m

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Computer-enhanced x-rays are called __________ scans.<br> A. TMS<br> B. PET<br> C. CT<br> D. MRI
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How to derive the fourth equation of motion?
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3 years ago
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak
Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

P = AI

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

A = \frac{\pi d^2}{4}

Now the intensity is inversely proportional to the square of the distance from the source, then

I \propto \frac{1}{r^2}

The expression for the intensity at different distance is

\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}

Here,

I_1 = Intensity at distance 1

I_2 = Intensity at distance 2

r_1 = Distance 1 from light source

r_2 = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

I_2 = I_1 (\frac{r_1^2}{r_2^2})

If we replace with our values at this equation we have,

I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})

I_2 = 1.11*10^{-4} W/m^2

Now using the equation to find the area we have that

A = \frac{\pi (8.4*10^{-3}m)^2}{4}

A = 5.5*10^{-5}m^2

Finally with the intensity and the area we can find the sound power, which is

P = AI

P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}J/s

Power is defined as the quantity of Energy per second, then

E = 6.1*10^{-9}J

8 0
4 years ago
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