Answer:
Explanation:
1.)
2.) COP
3.) Rate of heat absorption
COP
Therefore, cooling in minutes=
COP cannot cycle=
Rate of heat absorption
cooling time in minutes with cannot cycle
<span>v/2
This is an exercise in the conservation of momentum.
The collision specified is a non-elastic collision since the railroad cars didn't bounce away from each other. For the equations, I'll use the following variables.
r1 = momentum of railroad car 1
r2 = momentum of railroad car 2
x = velocity after collision
Prior to the collision, the momentum of the system was
r1 + r2
mv + m*0
So the total momentum is mv
After the collision, both cars move at the same velocity since it was non-elastic, so
r1 + r2
mx + mx
x(m + m)
x(2m)
And since the momentum has to match, we can set the equations equal to each other, so:
x(2m) = mv
x(2) = v
x = v/2
Therefore the speed immediately after collision was v/2</span>
To solve this problem it is necessary to apply the concept related to root mean square velocity, which can be expressed as
Where,
T = Temperature
R = Gas ideal constant
n = Number of moles in grams.
Our values are given as
The temperature is
Therefore the root mean square velocity would be
The fraction of velocity then can be calculated between the escape velocity and the root mean square velocity
Therefore the fraction of the scape velocity on the earth for molecula hydrogen is 0.1736
Answer:
C.....im just typing more now because of the rule that it has to be 20 characters long