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4 years ago

Solve for y. x y + p = 9 A) x(9-p) B) (p-9)/x C) (9-p)/x

1 answer:

7 0

x y + p = 9
subtract p on both sides
xy + p - p = 9 - p
simplify
xy = 9 - p
divide both sides by x
xy/x = (9-p)/x
simplify
y = (9 - p)/x

Answer
C) (9 - p)/x

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Read 2 more answers

Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L 18, start fraction, start text, L, end text, divided

Fiesta28 [93]

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4 years ago

P is inversely proportional to the cube of (q-2) p=6 when q=3 find the value of p when q is 5

sveticcg [70]

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{ k}}}{x}
\end{array}\\\\
-----------------------------\\\\
\textit{p is inversely proportional to the cube of (q-2)}\implies p=\cfrac{k}{(q-2)^3}
\\\\\\
now \quad 
\begin{cases}
p=6\\
q=3
\end{cases}\implies 6=\cfrac{k}{(3-2)^3}$

solve for "k", to find k or the "constant of variation"

then plug k's value back to $\bf p=\cfrac{k}{(q-2)^3}$

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