The are of the specific figure you have gave me is 57 I think I’m not really sure
Answer:
The solutions are 
Step-by-step explanation:
To factor this cubic polynomial
you must:
- Group the polynomial into two sections

- Factor out -9 from


- Factor out
from 


- Factor out common term



- Factor




- Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

The solutions are

1. 7x - 28 = 84
2. 7x = 112
3. x = 16