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maksim [4K]
3 years ago
7

Simplify the ratio 42:28:21

Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0
It would be 6:4:3 because you divide each number by a factor they all have in common, which would be 7.
Trava [24]3 years ago
4 0

Answer:  The required simplified ratio is 6 : 4 : 3.

Step-by-step explanation:  We are given to simplify the following ratio :

R=42:28:21.

We know that

for any two numbers a and b,

a:b=\dfrac{a}{b}.

We have

42:28=\dfrac{42}{28}=\dfrac{7\times6}{7\times4}=\dfrac{6}{4}.

And,

28:21=\dfrac{28}{21}=\dfrac{7\times4}{7\times3}=\dfrac{4}{3}.

Therefore, we get

42:28:21=6:4:3.

Thus, the required simplified ratio is 6 : 4 : 3.

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Set the length of the base as x, the two equal sides are then 4x each, so the perimeter is x+4x+4x=9x
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I can never get these answers right omggg I need help!
Alik [6]

Answer:

24-(L times 2) then divide the awnser by 2

Step-by-step explanation:

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A student says that the x-intercept of the graph of × + 2y =5 is the point (0,5). Is the student correct or incorrect? Explain y
ivanzaharov [21]

The student is incorrect, the actual x-intercept is (5, 0).

<h3>Is the student correct or incorrect?</h3>

Here we have the equation:

x + 2y = 5

The student says that the x-intercept is the point (0, 5).

So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).

So the point (0, 5) can't be an x-intercept.

For the given function:

x +2y = 5

The x-intercept is given by:

x + 2*0 = 5

x = 5

So it is (5 , 0).

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Three point zero one divided by seven
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The answer is zero point four three

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3 years ago
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For the square with side length n, the diagonal measures:

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<h3>How to get the length of the diagonal?</h3>

The sidelength of the square is n, and we want to get the length of the diagonal d.

Notice that the diagonal is the hypotenuse of a right triangle whose catheti measure n.

Then we can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the cathetus;

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