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Helen [10]
3 years ago
8

Recent revenue shortfalls in a southern state led to a reduction in the state budget for higher education. To offset the reducti

on, the largest state university proposed a 20% tuition increase. It was determined that such a large increase was needed to simply compensate for lost support from the state. Random samples of 100 freshmen, 100 sophomores, 100 juniors, and 100 seniors from the university were asked whether they were strongly opposed to the increase, given that it was the minimum increase necessary to maintain the university's budget at current levels. The results are given in the following table.
Strongly opposed

Freshman

Sophomore

Junior

Senior

Yes

78

72

58

36

No

22

28

42

64


To compare the four classes (freshman, sophomore, junior, senior) with respect to their opinion regarding the proposed tuition increase (yes = opposed, no = not opposed), which distribution should we calculate?

A)the joint distribution of year in school and opinion
B)the marginal distribution of year in school
C)the conditional distribution of opinion given year in school
D)the conditional distribution of year in school given opinion
Mathematics
1 answer:
Artemon [7]3 years ago
3 0

Answer:

The option (D) the conditional distribution of year in school given opinion

Step-by-step explanation:

Solution

Given that

Results:

Group 1

Category 1 =78  (61.00)  [4.74]

Category 2 = 72  (61.00)  [1.98]

Category 3 =58  (61.00)  [0.15]

Category 4= 36  (61.00)  [10.25]  

The row totals is = 244

GROUP 2

Category 1 = 22  (39.00)  [7.41]

Category 2 = 28  (39.00)  [3.10]

Category 3 = 42  (39.00)  [0.23]

Category 4 = 64  (39.00)  [16.03]

The row totals = 156

The column totals for both group 1 and 2 in categories (1 - 4) is = 400 totals, same as the row totals.

The distribution to calculate is, the conditional distribution of year in school given opinion

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Workers are grouped by their areas of expertise and are placed on at least one team. 20 are on the marketing team, 30 are on the
liubo4ka [24]

Answer: C. 74

Step-by-step explanation:

Let M= Number of workers are in marketing team .

S = Number of workers are in Sales team.

V = Number of workers are in Vision team.

As per given , we have

n(M) = 20 , n(S) = 30 , n(V) = 40

n(M∩S) = 5  ,  n(V∩S) = 6  ,  n(M∩V)  = 9

n(M∩S∩V) =4

Using formula of sets , we get

n(M∪S∪V) =n(M)+n(S) +n(V) -n(M∩S) - n(V∩S)-n(M∩V) +n(M∩S∩V)

Substitute the corresponding values , we get

n(M∪S∪V) =20+30+40-5-6-9 +4

=  74

∴ The number of workers are in at least one team = 74

Therefore , the total number of workers =74

Hence, the correct option is : C. 74

7 0
4 years ago
A sine function had an amplitude of 3, period of 6pi, horizontal shift of 3pi/2, & vertical shift of -1.
Simora [160]

Answer: \bold{y=\dfrac{1}{2}}

<u>Step-by-step explanation:</u>

f(x) = A sin (Bx - C) + D

  • amplitude = |A|
  • period =\dfrac{2\pi}{B}
  • phase shift =\dfrac{C}{B}
  • vertical shift = D

<u>A</u>

amplitude of 3 is given so  3 = |A| → A = ± 3, since it is stated that this is a positive function, then A = 3

<u>B</u>

period of 6π is given so 6\pi=\dfrac{2\pi}{B}\quad \rightarrow \quad B=\dfrac{2\pi}{6\pi}\quad \rightarrow \quad B=\dfrac{1}{3}

<u>C</u>

\text{phase shift is given as}\ \dfrac{3\pi}{2}\ \text{so}\ \dfrac{3\pi}{2}=\dfrac{C}{\frac{1}{3}}\quad \rightarrow\quad \dfrac{(\frac{1}{3})3\pi}{2}=C\quad \rightarrow\quad \dfrac{\pi}{2}=C

<u>D</u>

vertical shift of -1 is given so -1 = D


Now, substitute the values of A, B, C, and D into the formula (above):

f(x) = 3\ sin \bigg(\dfrac{1}{3}x - \dfrac{\pi}{2}\bigg) - 1


Next, solve when x = 2π

f(2\pi) = 3\ sin \bigg(\dfrac{1}{3}(2\pi) - \dfrac{\pi}{2}\bigg) - 1

        = 3\ sin \bigg(\dfrac{2\pi}{3} - \dfrac{\pi}{2}\bigg) - 1

        = 3\ sin \bigg(\dfrac{4\pi}{6} - \dfrac{3\pi}{6}\bigg) - 1

        = 3\ sin \bigg(\dfrac{\pi}{6}\bigg) - 1

        = 3\ \bigg(\dfrac{1}{2}\bigg) - 1

        =\dfrac{3}{2}-\dfrac{2}{2}

        =\dfrac{1}{2}

6 0
3 years ago
11. You have 8 cups of sugar. A recipe calls for cup of sugar. Another recipe
Drupady [299]

Answer:

6 cups of sugar left

hope this helps

7 0
3 years ago
Can anyone help me to solve the question
FrozenT [24]

Answer:

x = 2\sqrt{10}

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² + 9² = 11²

x² + 81 = 121 ( subtract 81 from both sides )

x² = 40 ( take square root of both sides )

x = \sqrt{40} = \sqrt{4(10)} = \sqrt{4} × \sqrt{10} = 2\sqrt{10} ≈ 6.32 ( to 2 dec. places )

3 0
2 years ago
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in a survey of a school 300 student favour to play volleyball 200 student favour to play cricket and 110 favour both find the nu
sweet [91]
If 110 students play both
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Also (the same) 200 play cricket, so only cricket play 90 students (200-110)
Answer: either volleyball or cricket is
(300-110)+(200-110) = 190+ 90 = 280
Answer: 280
3 0
3 years ago
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