There are three partial products in part a because both values, 273 and 346, have all numerical values, that aren't 0, so they can be multiplied and a value will be added.
There are only 2 partial products in part b because in 306, the tens place is worth 0 and anything times 0 = 0. There will be nothing to add for that value.
Okay I did the work and I think it’s either answer a or b but goodluck sorry
But I still don’t understand this.
Answer:
The angles of both figures are listed in the same order. The first angle of the first one is congruent to the first angle of the second, and the second angle of the first one is congruent to the second angle of the second figure, and so on.
Step-by-step explanation:
You have a repeated 'F' in naming the first figure, so I think you made an error. But the rule in my answer is true and you can apply it.
Answer:
10(q-3)
last option
please brainliest me btw
Step-by-step explanation:
The expression states 10q-30
The GCF is 10 (30 GCF by 10 Is 10)
Factor out 10
After, divide all the terms by 10
10 (10q/10) - 30/10
Simplify this and we get
10(q-3)
so in conclusion, it is the last option.
Both sides aren't equal because 1-sin^2x = cos^2x and cos^2x / 1+cosx can never equal cosx
