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Finger [1]
3 years ago
9

In geometry, Heron's formula (sometimes called Hero's formula), named after Hero of Alexandria, gives the area of a triangle by

requiring no arbitrary choice of side as base or vertex as origin, contrary to other formulae for the area of a triangle, such as half the base times the height. Use Heron's Formula to find the area, in square yards, of ΔABC.
A. 5.591
B. 7.385
C. 8.270
D. 6.495

Mathematics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

D. 6.495 ft²

Step-by-step explanation:

s = \frac{a+b+c}{2}        Substitute

s = \frac{7+3+5 }{2}        Add

s = 15/2          Divide

s = 7.5

Now use the equation for area

A = \sqrt{s(s-a)(s-b)(s-c)}       Substitute

A=\sqrt{7.5(7.5 - 7)(7.5-3)(7.5-5)   Subtract in the parentheses

A=\sqrt{7.5(0.5)(4.5)(2.5)}                      Multiply

A=\sqrt{42.1875}                                     Take the square root

A = 6.495 ft²

If this answer is correct, please make me Brainliest!

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Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

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P(X= 2) = 0.0486

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Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

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Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

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Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

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