Just take a calculator and divide 4 by 10 exactly how you see it. Or just divide it like you normally would any number on paper. 0.4 is your answer.
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
did she like it?
Step-by-step explanation:
Answer:Exact Form:
1/2
Step-by-step explanation:
3÷?=36
multiply both sides by 3 to figure out what "?" is
36*3=108
3÷108=36
?=108
