Ask question

Ask question

All categories

3 years ago

8

When the value of the y-intercept(b) change by subtracting a number from "b" in the equation "y=mx+b", the graph will move of sh

ift down ? true or false

1 answer:

ehidna [41]3 years ago

6 0

Answer:

True. The graph will shift down if we subtract a number from "b"

Step-by-step explanation:

"b" represents the y-intercept, or how high up on the y axis the graph intersects.

If we don't change anything except for the y-intercept, then the graph should only move up or down.

Because we are decreasing the value of "b" the y intercept will decrease, dragging the graph of y down.

You might be interested in

Jade needs 5 pounds of ground beef to make lasagna for a family reunion one package of ground beef weighs 2 1/2 pounds another p

Ivanshal [37]

Jays would have 1/10 of a pound left. This is the answer considering that 2 35 is 2 3/5 you find the common denominator then add the ywo then take away five.

7 0

2 years ago

Read 2 more answers

A person who weighs 100 pounds on Earth weighs 16.5 pounds on the Moon. If a boy weighs 60 pounds on Earth, how much does he wei

xxMikexx [17]

10 pounds you divide your weight by 6

8 0

3 years ago

To get from one town to another, Jack must travel 7 miles east and 24 miles south. What is the direct distance between the two t

Step2247 [10]

The 7 miles and 24 miles make up two "legs" of a right triangle.
The third side (or hypotenuse) is the distance between the towns.
distance^2 = 7^2 + 24^2
distance^2 = 49 + 576
distance^2 = 625
distance = square root of 625 or 25

3 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Recycling Center A processes aluminum at a rate of 100 pounds per hour, while Recycling Center B processes aluminum at a rate of

maria [59]

I believe it is Recycling center A

6 0

2 years ago

Read 2 more answers