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3 years ago

Can someone answer this Please!?!?

Mathematics

1 answer:

tangare [24]3 years ago

5 0

Answer:

i would lol but im stupid

Step-by-step explanation:

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Help please someone

kenny6666 [7]

Answer: step by step explanation

it's just that you have to multiply the number under root and it's any number is square then you can take it out of root.

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2 years ago

What is the length of PR? ___ units

ANTONII [103]

I hope this helps you

5 0

2 years ago

Read 2 more answers

Divide -2x^3-5x^2+4x+2 by x+2

erik [133]

Answer:

The correct option is C. $-2x^2-x+6, R(-10)$

Explanation:

Given:

Dividend = -2x^3-5x^2+4x+2

Divider =(x+2)

Solution:

Now by using the division method , we will find out the quotient and remainder of the given equation

And the equation will become

$-2x^3-5x^2+4x+2=(x+2)(-2x^2-x+6)-10$

So , We will get the quotient = $-2x^2-x+6$

And Remainder = -10

Hence the Correct option which perfectly satisfy the given equation is C.

4 0

2 years ago

What is the mean absolute deviation of the following set of data 4 6 2 8

babymother [125]

Answer:

srry i really need points

Step-by-step explanation:

6 0

2 years ago

Which equation represents the circle described? (in picture)

Sedaia [141]

You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

$x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24$

Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}$

So the answer is C (the same left side of equation).

6 0

3 years ago