Answer:
a) No. t < 0 is not part of the useful domain of the function
b) 2.0 seconds
Step-by-step explanation:
a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.
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b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.
h = 0 = -16t² +28t +8 . . . . . . . . . . . . the ball hits the ground when h = 0
0 = -4(4t² -7t -2) = -4(4t +1)(t -2)
This has t-intercepts where the factors are zero, at t=-1/4 and t=2.
The ball will hit the ground after 2 seconds.
Oh ok. So I think that x is 83. Because I did this 630-100-121-106-112-108=83. And then I did 630/6 and got 105 and thats the mean.
Answer: 1. x= -12 2. x= 12
Step-by-step explanation:
1. 5(+3)=−45
5x+15−15=−45−15
5x= -60
5x/5 = -60/5
x = -60/5
x= -12
2. 1x/2−4=2
x/2 -4=22−4+4=2+4
/2=6
2⋅2=2⋅6
x=2⋅6
x= 12
It is understood without being written that the slope of this line is 1. If we rewrite the point-slope form of the line it would be y-8=1(x-4) where 1 is the slope. We move the -8 over by addition to get y = 1x-4+8, or, simplified, y=x+4, the first choice in your answers.