Answer:
Ming rented the bike for 8 hours. Hope this helps!
I'll explain how to do the first one:-
y = cos-1(x2)
This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.
We need to apply the chain rule.
Personally I find this easier to understand if i let u = x^2, so
If y = f(u) and u is a function of x then
dy/dx = dy/ du * du/dx
Here u = x^2 and y = cos-1(u)
du/dx = 2x
so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx
= -1 / √(1 - u^2) * 2x
= -2x / √(1 - u^2)
= -2x / √(1 - (x^2)^2)
= -2x / √(1 - x^4)
I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.
Answer:
a=1 is the answer
Step-by-step explanation:
let
p(x)=x³-2ax²+16
put x= -2
p(-2)=(-2)³-2a(-2)²+16
p(-2)=-8+16-8a
p(-2)=8-8a
as (x+2) is a factor of p(x) then p(x) is equal to zero
8-8a=0
8=8a
a=1
i hope this will help you
