Question

Solve 2x2 + x − 4 = 0. x2 + x + = 0

Answer 1

Answer:

2x^2+x-4=0

x^2+\dfrac12x-2=0

x^2+\dfrac12x+\dfrac1{16}-\dfrac{33}{16}=0

\left(x+\dfrac14\right)^2=\dfrac{33}{16}

x+\dfrac14=\pm\dfrac{\sqrt{33}}4

x=\dfrac{-1\pm\sqrt{33}}4

Step-by-step explanation:

Answer 2

Answer:

2x^2+x-4=0

x^2+\dfrac12x-2=0

x^2+\dfrac12x+\dfrac1{16}-\dfrac{33}{16}=0

\left(x+\dfrac14\right)^2=\dfrac{33}{16}

x+\dfrac14=\pm\dfrac{\sqrt{33}}4

x=\dfrac{-1\pm\sqrt{33}}4

Step-by-step explanation: lol tooooo much ∅∞