When a hostname is configured through the Cisco CLI, some naming conventions must be follows.
These naming conventions are as follows:
1- The name of the host must always begin with a letter
2- The name of the host cannot contain any spaces
3- The length of the hostname should always be less than 64 letters
Answer:
Myelodysplastic (Ans. A)
Explanation:
Acute myeloblastic leukemia (AML): Is also called malignant blood cell cancer which can affect both adults & children. It is a fast-growing malignant disease where too many immature myeloblasts (WBS) are found in the RBC & bone marrow. Acute myeloblastic leukemia starts while chronic leukemia present from a long time & grow gradually. Symptoms of acute myeloblastic leukemia are:
High fever, a large no. of infections over a short period, pain in the joints, sweating a lot, etc.
Myelodysplastic syndrome: It is a group of disorder caused by blood cells (which is immature & don't work properly). Instead of developing properly the blood cells die in the bone marrow. After sometimes there are more immature cells than healthy ones, causing the problems infection caused by leukopenia, etc.
Answer:
Approximately 6944 glucose residues are added enzymatically per second
Explanation:
Cellulose is the main structural polysaccharides in plants. It is composed of unbranched glucose monomer units linked to each other by beta 1-4 glycosidic bonds.
The cell wall and stem of plants cells are composed of cellulose fibers. They provide rigidity and support to the plant.
In the given bamboo plant, the enzymatic addition of glucose units to the growing cellulose fiber chains results in the phenomenal growth rate of the bamboo stem.
Since each glucose unit contributes ~0.5 nm to the length of a cellulose molecule, number of glucose units required for daily growth is calculated as follows:
0.5 nm = 10⁻⁹
0.3 m/0.5 x 10⁻⁹ m = 600000000 units of glucose per day
Number of seconds in a day = 24 * 60 * 60 = 86400 seconds
Number of glucose residues added per second = 600000000/86400
Number of glucose residues added per second = 6944.4 glucose molecules per second
Therefore, approximately 6944 glucose residues are added per second
The answer is d
Both b and c
Answer:
If you cut a starfish radially (cut passing through the centre of the body) in five parts, every part will regrow into a new fully developed star fish.
