There are 4 possibilities:
1) No event happens
2) event A happens, not event B
3) event B happens, not event A
4) both events happen
seeing as there is a 50% chance of either event happening, I would assume that all 4 possibilities have an equal chance of happening
so if there are 4 events, then each one is 25% likely.
So the probability if them both occurring is 25%
I think
The answer to the question is: Yes.
Explanation: It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.
Since I'm here already, here is the solution to this one:
6x² + 18x = 0
Divide each side of the equation by 6 :
x² + 3x = 0
Factor the left side:
x(x+ 3) = 0
This statement is true if x=0 or if x=3.
The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
So,
All you have to do is find the total labor cost and put it over the revenue.
We have two workers each earning $8/hr. (lousy), and they work 40 hrs./week.
2 * $8 = $16/hr.
$16/hr. * 40 hrs. = $640

Cross out zeros.

Simplify.



Convert the denominator to 100.


=
32%
The labor cost is 32% of the revenue.
Answer:
6+18 pls give brainlest
Step-by-step explanation:
How to solve your problem
3(2+6)
Simplify
1
Distribute
3(2+6)
6+18
Solution
6+18